Convert a sentence into its equivalent mobile numeric keypad sequence

 

PROBLEM 55: Convert a sentence into its equivalent mobile numeric keypad sequence

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Problem Reference : GeeksForGeeks

Author : Ajay Zad

Date    : 17/04/2023

Given a sentence in the form of a string in uppercase, convert it into its equivalent mobile numeric keypad sequence. Please note there might be spaces in between the words in a sentence and we can print spaces by pressing 0.

 

SOLUTION:

class Solution:
    def printSequence(self,S):
         s1 = ""
         for i in S:
            if i == 'A':
                s1 = s1 + '2'
            elif i == 'B':
                s1 = s1 + '22'
            elif i == 'C':
                s1 = s1 + '222'
            elif i == 'D':
                s1 = s1 + '3'
            elif i == 'E':
                s1 = s1 + '33'
            elif i == 'F':
                s1 = s1 + '333'
            elif i == 'G':
                s1 = s1 + '4'
            elif i == 'H':
                s1 = s1 + '44' 
            elif i == 'I':
                s1 = s1 + '444' 
            elif i == 'J':
                s1 = s1 + '5' 
            elif i == 'K':
                s1 = s1 + '55'
            elif i == 'L':
                s1 = s1 + '555' 
            elif i == 'M':
                s1 = s1 + '6' 
            elif i == 'N':
                s1 = s1 + '66' 
            elif i == 'O':
                s1 = s1 + '666' 
            elif i == 'P':
                s1 = s1 + '7'
            elif i == 'Q':
                s1 = s1 + '77'
            elif i == 'R':
                s1 = s1 + '777'
            elif i == 'S':
                s1 = s1 + '7777'
            elif i == 'T':
                s1 = s1 + '8'
            elif i == 'U':
                s1 = s1 + '88'
            elif i == 'V':
                s1 = s1 + '888' 
            elif i == 'W':
                s1 = s1 + '9' 
            elif i == 'X':
                s1 = s1 + '99' 
            elif i == 'Y':
                s1 = s1 + '999'
            elif i == 'Z':
                s1 = s1 + '9999' 
            else:
                s1 = s1 + '0'
        print(s1)

Example 1:

Input:
S = "GFG"
Output: 43334
Explanation: For 'G' press '4' one time.
For 'F' press '3' three times.

Example 2:

Input:
S = "HEY U"
Output: 4433999088
Explanation: For 'H' press '4' two times.
For 'E' press '3' two times. For 'Y' press '9' 
three times. For white space press '0' one time.
For 'U' press '8' two times.

 Expected Time Complexity: O(Length of String)

Expected Auxiliary Space: O(Length of String)
 

Constraints:

1 <= Length of String <= 105
Characters of string can be empty space or capital alphabets.